If 10 lbs. of refrigerant passing through a water cooled condenser gives up 20 Btu's of heat per lb, what is the temperature of the water leaving the condenser if it enters at 80°F?

To determine the temperature of the water leaving the condenser, it's essential to understand the heat exchange taking place between the refrigerant and the water. When the refrigerant gives up heat, this heat is absorbed by the water, raising its temperature.

In this scenario, we have 10 pounds of refrigerant, and it releases 20 Btu of heat per pound. Therefore, the total heat released by the refrigerant can be calculated by multiplying the mass of the refrigerant by the amount of heat released per pound:

Total heat released = 10 lbs * 20 Btu/lb = 200 Btu.

This 200 Btu is then transferred to the water. The increase in water temperature can be determined by using the formula:

Heat absorbed = mass of water * specific heat of water * change in temperature.

Assuming we are dealing with a typical water mass flow rate (if not stated, we can assume an amount for demonstration, such as 1 lb for simplicity):

1. The specific heat of water is approximately 1 Btu/lb°F.

2. If we let the mass of the water be 1 lb, then the change in temperature can be found by rearranging the formula:

Change in temperature = Heat absorbed /